Ato H. answered • 12/06/12

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The answer below is totally wrong!! How can the diagonal have a greater magnitude than the Area. You solve it like this instead :

First find the length of each side of the square by: √(Area)= Length of each side of square, which is √16 = 4 cm

Now divide the square into two isosceles right triangles with the diagonal.

Working on one of the triangles, apply Pythagorean Theorem i.e.

(Diagonal)^{2} = (4)^{2} + (4)^{2 }the 4's come from the sides of the square that no form two equal sides of i the isosceles right triangle

so (Diagonal)^{2} = 32

√(Diagonal)^{2 = }√(32)

Diagonal= 4√2 cm OR

≈5.65685424949 cm :-)